Hi,
I have a bash script similar to the one below:
#!/bin/bash
NEW_FILE=test
touch ${NEW_FILE}_test
Note that I'm using {} to denote the variable name. If the {} is not present, it will consider the variable name as NEW_FILE_test instead of NEW_FILE.
If the same script is used in a Bash step, it will fail since it expects a QuickBuild variable within ${}.
- solved #2
- replies 2
- views 1423
- stars 0